y(4y-57)=0

Solution for y(4y-57)=0 equation:

y(4y-57)=0

We multiply parentheses

4y^2-57y=0

a = 4; b = -57; c = 0;
Δ = b2-4ac
Δ = -572-4·4·0
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-57}{2*4}=\frac{0}{8}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+57}{2*4}=\frac{114}{8}
=14+1/4
$