y(n+2)-2y(n+1)+y(n)=2

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Solution for y(n+2)-2y(n+1)+y(n)=2 equation: 


Simplifying
y(n + 2) + -2y(n + 1) + y(n) = 2

Reorder the terms:
y(2 + n) + -2y(n + 1) + y(n) = 2
(2 * y + n * y) + -2y(n + 1) + y(n) = 2

Reorder the terms:
(ny + 2y) + -2y(n + 1) + y(n) = 2
(ny + 2y) + -2y(n + 1) + y(n) = 2

Reorder the terms:
ny + 2y + -2y(1 + n) + y(n) = 2
ny + 2y + (1 * -2y + n * -2y) + y(n) = 2

Reorder the terms:
ny + 2y + (-2ny + -2y) + y(n) = 2
ny + 2y + (-2ny + -2y) + y(n) = 2

Multiply y * n
ny + 2y + -2ny + -2y + ny = 2

Reorder the terms:
ny + -2ny + ny + 2y + -2y = 2

Combine like terms: ny + -2ny = -1ny
-1ny + ny + 2y + -2y = 2

Combine like terms: -1ny + ny = 0
0 + 2y + -2y = 2
2y + -2y = 2

Combine like terms: 2y + -2y = 0
0 = 2

Solving
0 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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