y(y+2)+2(y+2)=

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Solution for y(y+2)+2(y+2)= equation:


Simplifying
y(y + 2) + 2(y + 2) = 0

Reorder the terms:
y(2 + y) + 2(y + 2) = 0
(2 * y + y * y) + 2(y + 2) = 0
(2y + y2) + 2(y + 2) = 0

Reorder the terms:
2y + y2 + 2(2 + y) = 0
2y + y2 + (2 * 2 + y * 2) = 0
2y + y2 + (4 + 2y) = 0

Reorder the terms:
4 + 2y + 2y + y2 = 0

Combine like terms: 2y + 2y = 4y
4 + 4y + y2 = 0

Solving
4 + 4y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(2 + y)(2 + y) = 0

Subproblem 1

Set the factor '(2 + y)' equal to zero and attempt to solve: Simplifying 2 + y = 0 Solving 2 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + y = 0 + -2 y = 0 + -2 Combine like terms: 0 + -2 = -2 y = -2 Simplifying y = -2

Subproblem 2

Set the factor '(2 + y)' equal to zero and attempt to solve: Simplifying 2 + y = 0 Solving 2 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + y = 0 + -2 y = 0 + -2 Combine like terms: 0 + -2 = -2 y = -2 Simplifying y = -2

Solution

y = {-2, -2}

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