y(y+2)-8y=14+y(y-4)

Solution for y(y+2)-8y=14+y(y-4) equation:

y(y+2)-8y=14+y(y-4)

We move all terms to the left:

y(y+2)-8y-(14+y(y-4))=0

We add all the numbers together, and all the variables

-8y+y(y+2)-(14+y(y-4))=0

We multiply parentheses

y^2-8y+2y-(14+y(y-4))=0


We calculate terms in parentheses: -(14+y(y-4)), so:

14+y(y-4)

determiningTheFunctionDomain
y(y-4)+14

We multiply parentheses

y^2-4y+14

Back to the equation:

-(y^2-4y+14)


We add all the numbers together, and all the variables

y^2-6y-(y^2-4y+14)=0

We get rid of parentheses

y^2-y^2-6y+4y-14=0

We add all the numbers together, and all the variables

-2y-14=0

We move all terms containing y to the left, all other terms to the right

-2y=14

y=14/-2

y=-7