y(y+2)-y(y-4)-10=20

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Solution for y(y+2)-y(y-4)-10=20 equation:


Simplifying
y(y + 2) + -1y(y + -4) + -10 = 20

Reorder the terms:
y(2 + y) + -1y(y + -4) + -10 = 20
(2 * y + y * y) + -1y(y + -4) + -10 = 20
(2y + y2) + -1y(y + -4) + -10 = 20

Reorder the terms:
2y + y2 + -1y(-4 + y) + -10 = 20
2y + y2 + (-4 * -1y + y * -1y) + -10 = 20
2y + y2 + (4y + -1y2) + -10 = 20

Reorder the terms:
-10 + 2y + 4y + y2 + -1y2 = 20

Combine like terms: 2y + 4y = 6y
-10 + 6y + y2 + -1y2 = 20

Combine like terms: y2 + -1y2 = 0
-10 + 6y + 0 = 20
-10 + 6y = 20

Solving
-10 + 6y = 20

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 6y = 20 + 10

Combine like terms: -10 + 10 = 0
0 + 6y = 20 + 10
6y = 20 + 10

Combine like terms: 20 + 10 = 30
6y = 30

Divide each side by '6'.
y = 5

Simplifying
y = 5

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