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y(y+4)=-4
We move all terms to the left:
y(y+4)-(-4)=0
We add all the numbers together, and all the variables
y(y+4)+4=0
We multiply parentheses
y^2+4y+4=0
a = 1; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{-4}{2}=-2$
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