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y(y-12)=30+y(y+3)
We move all terms to the left:
y(y-12)-(30+y(y+3))=0
We multiply parentheses
y^2-12y-(30+y(y+3))=0
We calculate terms in parentheses: -(30+y(y+3)), so:We get rid of parentheses
30+y(y+3)
determiningTheFunctionDomain y(y+3)+30
We multiply parentheses
y^2+3y+30
Back to the equation:
-(y^2+3y+30)
y^2-y^2-12y-3y-30=0
We add all the numbers together, and all the variables
-15y-30=0
We move all terms containing y to the left, all other terms to the right
-15y=30
y=30/-15
y=-2
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