y(y-12)=30+y(y+3)

Solution for y(y-12)=30+y(y+3) equation:

y(y-12)=30+y(y+3)

We move all terms to the left:

y(y-12)-(30+y(y+3))=0

We multiply parentheses

y^2-12y-(30+y(y+3))=0


We calculate terms in parentheses: -(30+y(y+3)), so:

30+y(y+3)

determiningTheFunctionDomain
y(y+3)+30

We multiply parentheses

y^2+3y+30

Back to the equation:

-(y^2+3y+30)


We get rid of parentheses

y^2-y^2-12y-3y-30=0

We add all the numbers together, and all the variables

-15y-30=0

We move all terms containing y to the left, all other terms to the right

-15y=30

y=30/-15

y=-2