y(y-2)+8=3(y-4)-2

Solution for y(y-2)+8=3(y-4)-2 equation:

y(y-2)+8=3(y-4)-2

We move all terms to the left:

y(y-2)+8-(3(y-4)-2)=0

We multiply parentheses

y^2-2y-(3(y-4)-2)+8=0


We calculate terms in parentheses: -(3(y-4)-2), so:

3(y-4)-2

We multiply parentheses

3y-12-2

We add all the numbers together, and all the variables

3y-14

Back to the equation:

-(3y-14)


We get rid of parentheses

y^2-2y-3y+14+8=0

We add all the numbers together, and all the variables

y^2-5y+22=0

a = 1; b = -5; c = +22;
Δ = b2-4ac
Δ = -52-4·1·22
Δ = -63
Delta is less than zero, so there is no solution for the equation