y(y-2)+8=3(y-4)-2

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Solution for y(y-2)+8=3(y-4)-2 equation:



y(y-2)+8=3(y-4)-2
We move all terms to the left:
y(y-2)+8-(3(y-4)-2)=0
We multiply parentheses
y^2-2y-(3(y-4)-2)+8=0
We calculate terms in parentheses: -(3(y-4)-2), so:
3(y-4)-2
We multiply parentheses
3y-12-2
We add all the numbers together, and all the variables
3y-14
Back to the equation:
-(3y-14)
We get rid of parentheses
y^2-2y-3y+14+8=0
We add all the numbers together, and all the variables
y^2-5y+22=0
a = 1; b = -5; c = +22;
Δ = b2-4ac
Δ = -52-4·1·22
Δ = -63
Delta is less than zero, so there is no solution for the equation

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