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y+(2/3)=(1/4)y-1
We move all terms to the left:
y+(2/3)-((1/4)y-1)=0
Domain of the equation: 4)y-1)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
y-((+1/4)y-1)+(+2/3)=0
We get rid of parentheses
y-((+1/4)y-1)+2/3=0
We calculate fractions
y+()/4y-1)*3)+8y/4y-1)*3)=0
We calculate fractions
y+(()*4y)/16y^2+(-1)*3)+8y*4y)/16y^2=0
We multiply all the terms by the denominator
y*16y^2+(()*4y)+(-1)*3)+8y*4y)=0
We calculate terms in parentheses: +(()*4y), so:Wy multiply elements
()*4y
16y^3+(()*4y)+(-1)*3)+8y*4y)=0
We get rid of parentheses
16y^3+(()*4y)-1)*3)+8y*4y=0
We calculate terms in parentheses: +(()*4y), so:We do not support eypression: y^3
()*4y
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