y+(y+1)+(y+2)+(y+3)=406

Solution for y+(y+1)+(y+2)+(y+3)=406 equation:

Simplifying
y + (y + 1) + (y + 2) + (y + 3) = 406

Reorder the terms:
y + (1 + y) + (y + 2) + (y + 3) = 406

Remove parenthesis around (1 + y)
y + 1 + y + (y + 2) + (y + 3) = 406

Reorder the terms:
y + 1 + y + (2 + y) + (y + 3) = 406

Remove parenthesis around (2 + y)
y + 1 + y + 2 + y + (y + 3) = 406

Reorder the terms:
y + 1 + y + 2 + y + (3 + y) = 406

Remove parenthesis around (3 + y)
y + 1 + y + 2 + y + 3 + y = 406

Reorder the terms:
1 + 2 + 3 + y + y + y + y = 406

Combine like terms: 1 + 2 = 3
3 + 3 + y + y + y + y = 406

Combine like terms: 3 + 3 = 6
6 + y + y + y + y = 406

Combine like terms: y + y = 2y
6 + 2y + y + y = 406

Combine like terms: 2y + y = 3y
6 + 3y + y = 406

Combine like terms: 3y + y = 4y
6 + 4y = 406

Solving
6 + 4y = 406

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 4y = 406 + -6

Combine like terms: 6 + -6 = 0
0 + 4y = 406 + -6
4y = 406 + -6

Combine like terms: 406 + -6 = 400
4y = 400

Divide each side by '4'.
y = 100

Simplifying
y = 100