y+(y+2)+2(y+2)=58

Solution for y+(y+2)+2(y+2)=58 equation:

Simplifying
y + (y + 2) + 2(y + 2) = 58

Reorder the terms:
y + (2 + y) + 2(y + 2) = 58

Remove parenthesis around (2 + y)
y + 2 + y + 2(y + 2) = 58

Reorder the terms:
y + 2 + y + 2(2 + y) = 58
y + 2 + y + (2 * 2 + y * 2) = 58
y + 2 + y + (4 + 2y) = 58

Reorder the terms:
2 + 4 + y + y + 2y = 58

Combine like terms: 2 + 4 = 6
6 + y + y + 2y = 58

Combine like terms: y + y = 2y
6 + 2y + 2y = 58

Combine like terms: 2y + 2y = 4y
6 + 4y = 58

Solving
6 + 4y = 58

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 4y = 58 + -6

Combine like terms: 6 + -6 = 0
0 + 4y = 58 + -6
4y = 58 + -6

Combine like terms: 58 + -6 = 52
4y = 52

Divide each side by '4'.
y = 13

Simplifying
y = 13