y+1/y+5=y-2/y+4+1

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Solution for y+1/y+5=y-2/y+4+1 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+1/y+5 = y-(2/y)+1+4 // - y-(2/y)+1+4

y-y+1/y+2/y-4-1+5 = 0

3*y^-1 = 0 // : 3

y^-1 = 0

y naleu017Cy do O

y belongs to the empty set

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