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y+1/y=12
We move all terms to the left:
y+1/y-(12)=0
Domain of the equation: y!=0We multiply all the terms by the denominator
y∈R
y*y-12*y+1=0
We add all the numbers together, and all the variables
-12y+y*y+1=0
Wy multiply elements
y^2-12y+1=0
a = 1; b = -12; c = +1;
Δ = b2-4ac
Δ = -122-4·1·1
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{35}}{2*1}=\frac{12-2\sqrt{35}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{35}}{2*1}=\frac{12+2\sqrt{35}}{2} $
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