y+10+4y-48=y+47

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Solution for y+10+4y-48=y+47 equation: 



y+10+4y-48=y+47

We move all terms to the left:

y+10+4y-48-(y+47)=0

We add all the numbers together, and all the variables

5y-(y+47)-38=0

We get rid of parentheses

5y-y-47-38=0

We add all the numbers together, and all the variables

4y-85=0

We move all terms containing y to the left, all other terms to the right

4y=85

y=85/4

y=21+1/4

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