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y+10-3/y=7
We move all terms to the left:
y+10-3/y-(7)=0
Domain of the equation: y!=0We add all the numbers together, and all the variables
y∈R
y-3/y+3=0
We multiply all the terms by the denominator
y*y+3*y-3=0
We add all the numbers together, and all the variables
3y+y*y-3=0
Wy multiply elements
y^2+3y-3=0
a = 1; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·1·(-3)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{21}}{2*1}=\frac{-3-\sqrt{21}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{21}}{2*1}=\frac{-3+\sqrt{21}}{2} $
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