y+10=3-4(2y+5)

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Solution for y+10=3-4(2y+5) equation: 



y+10=3-4(2y+5)

We move all terms to the left:

y+10-(3-4(2y+5))=0



We calculate terms in parentheses: -(3-4(2y+5)), so:

3-4(2y+5)

determiningTheFunctionDomain
-4(2y+5)+3

We multiply parentheses

-8y-20+3

We add all the numbers together, and all the variables

-8y-17

Back to the equation:

-(-8y-17)



We get rid of parentheses

y+8y+17+10=0

We add all the numbers together, and all the variables

9y+27=0

We move all terms containing y to the left, all other terms to the right

9y=-27

y=-27/9

y=-3

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