y+1=10-2(y-3)

Solution for y+1=10-2(y-3) equation:

y+1=10-2(y-3)

We move all terms to the left:

y+1-(10-2(y-3))=0


We calculate terms in parentheses: -(10-2(y-3)), so:

10-2(y-3)

determiningTheFunctionDomain
-2(y-3)+10

We multiply parentheses

-2y+6+10

We add all the numbers together, and all the variables

-2y+16

Back to the equation:

-(-2y+16)


We get rid of parentheses

y+2y-16+1=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5