y+1=2(y+3)-3(y-1)

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Solution for y+1=2(y+3)-3(y-1) equation: 



y+1=2(y+3)-3(y-1)

We move all terms to the left:

y+1-(2(y+3)-3(y-1))=0



We calculate terms in parentheses: -(2(y+3)-3(y-1)), so:

2(y+3)-3(y-1)

We multiply parentheses

2y-3y+6+3

We add all the numbers together, and all the variables

-1y+9

Back to the equation:

-(-1y+9)



We get rid of parentheses

y+1y-9+1=0

We add all the numbers together, and all the variables

2y-8=0

We move all terms containing y to the left, all other terms to the right

2y=8

y=8/2

y=4

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