y+2(3y+1)=16

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Solution for y+2(3y+1)=16 equation: 



y+2(3y+1)=16

We move all terms to the left:

y+2(3y+1)-(16)=0

We multiply parentheses

y+6y+2-16=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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