y+2(4-y)=6-(4y-12)

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Solution for y+2(4-y)=6-(4y-12) equation: 



y+2(4-y)=6-(4y-12)

We move all terms to the left:

y+2(4-y)-(6-(4y-12))=0

We add all the numbers together, and all the variables

y+2(-1y+4)-(6-(4y-12))=0

We multiply parentheses

y-2y-(6-(4y-12))+8=0



We calculate terms in parentheses: -(6-(4y-12)), so:

6-(4y-12)

determiningTheFunctionDomain
-(4y-12)+6

We get rid of parentheses

-4y+12+6

We add all the numbers together, and all the variables

-4y+18

Back to the equation:

-(-4y+18)



We add all the numbers together, and all the variables

-1y-(-4y+18)+8=0

We get rid of parentheses

-1y+4y-18+8=0

We add all the numbers together, and all the variables

3y-10=0

We move all terms containing y to the left, all other terms to the right

3y=10

y=10/3

y=3+1/3

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