y+2(y+1)+3=5y-1

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Solution for y+2(y+1)+3=5y-1 equation: 



y+2(y+1)+3=5y-1

We move all terms to the left:

y+2(y+1)+3-(5y-1)=0

We multiply parentheses

y+2y-(5y-1)+2+3=0

We get rid of parentheses

y+2y-5y+1+2+3=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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