y+2(y+4)=1+3(y+2)

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Solution for y+2(y+4)=1+3(y+2) equation: 


Simplifying
y + 2(y + 4) = 1 + 3(y + 2)

Reorder the terms:
y + 2(4 + y) = 1 + 3(y + 2)
y + (4 * 2 + y * 2) = 1 + 3(y + 2)
y + (8 + 2y) = 1 + 3(y + 2)

Reorder the terms:
8 + y + 2y = 1 + 3(y + 2)

Combine like terms: y + 2y = 3y
8 + 3y = 1 + 3(y + 2)

Reorder the terms:
8 + 3y = 1 + 3(2 + y)
8 + 3y = 1 + (2 * 3 + y * 3)
8 + 3y = 1 + (6 + 3y)

Combine like terms: 1 + 6 = 7
8 + 3y = 7 + 3y

Add '-3y' to each side of the equation.
8 + 3y + -3y = 7 + 3y + -3y

Combine like terms: 3y + -3y = 0
8 + 0 = 7 + 3y + -3y
8 = 7 + 3y + -3y

Combine like terms: 3y + -3y = 0
8 = 7 + 0
8 = 7

Solving
8 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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