y+2(y-5)=2y+22

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Solution for y+2(y-5)=2y+22 equation: 



y+2(y-5)=2y+22

We move all terms to the left:

y+2(y-5)-(2y+22)=0

We multiply parentheses

y+2y-(2y+22)-10=0

We get rid of parentheses

y+2y-2y-22-10=0

We add all the numbers together, and all the variables

y-32=0

We move all terms containing y to the left, all other terms to the right

y=32

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