y+2(y-5)=y2+2

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Solution for y+2(y-5)=y2+2 equation: 



y+2(y-5)=y2+2

We move all terms to the left:

y+2(y-5)-(y2+2)=0

We add all the numbers together, and all the variables

-(+y^2+2)+y+2(y-5)=0

We multiply parentheses

-(+y^2+2)+y+2y-10=0

We get rid of parentheses

-y^2+y+2y-2-10=0

We add all the numbers together, and all the variables

-1y^2+3y-12=0

a = -1; b = 3; c = -12;
Δ = b2-4ac
Δ = 32-4·(-1)·(-12)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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