y+2-5(-2y-2)=3(y-2)

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Solution for y+2-5(-2y-2)=3(y-2) equation: 



y+2-5(-2y-2)=3(y-2)

We move all terms to the left:

y+2-5(-2y-2)-(3(y-2))=0

We multiply parentheses

y+10y-(3(y-2))+10+2=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We add all the numbers together, and all the variables

11y-(3y-6)+12=0

We get rid of parentheses

11y-3y+6+12=0

We add all the numbers together, and all the variables

8y+18=0

We move all terms containing y to the left, all other terms to the right

8y=-18

y=-18/8

y=-2+1/4

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