y+2/y-2+1y-3/y-5

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Solution for y+2/y-2+1y-3/y-5 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+1*y+2/y-(3/y)-5-2 = 0

y+y+2/y-3*y^-1-5-2 = 0

2*y^1-1*y^-1-7*y^0 = 0

(2*y^2-7*y^1-1*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^2-7*y^1-1*y^0) = 0

y^1

2*y^2-7*y-1 = 0

2*y^2-7*y-1 = 0

DELTA = (-7)^2-(-1*2*4)

DELTA = 57

DELTA > 0

y = (57^(1/2)+7)/(2*2) or y = (7-57^(1/2))/(2*2)

y = (57^(1/2)+7)/4 or y = (7-57^(1/2))/4

y in { (7-57^(1/2))/4, (57^(1/2)+7)/4} 

y in { (7-57^(1/2))/4, (57^(1/2)+7)/4 }

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