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y+2=(1)/(2)(10y+4)
We move all terms to the left:
y+2-((1)/(2)(10y+4))=0
Domain of the equation: 2(10y+4))!=0We multiply all the terms by the denominator
y∈R
y*2(10y+4))-(1+2*2(10y+4))=0
Wy multiply elements
2y^2(1+4y(1=0
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