y+2=(5y-4)-(3y-1)

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Solution for y+2=(5y-4)-(3y-1) equation:



y+2=(5y-4)-(3y-1)
We move all terms to the left:
y+2-((5y-4)-(3y-1))=0
We calculate terms in parentheses: -((5y-4)-(3y-1)), so:
(5y-4)-(3y-1)
We get rid of parentheses
5y-3y-4+1
We add all the numbers together, and all the variables
2y-3
Back to the equation:
-(2y-3)
We get rid of parentheses
y-2y+3+2=0
We add all the numbers together, and all the variables
-1y+5=0
We move all terms containing y to the left, all other terms to the right
-y=-5
y=-5/-1
y=+5

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