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y+2y+(y-3)=125
We move all terms to the left:
y+2y+(y-3)-(125)=0
We add all the numbers together, and all the variables
3y+(y-3)-125=0
We get rid of parentheses
3y+y-3-125=0
We add all the numbers together, and all the variables
4y-128=0
We move all terms containing y to the left, all other terms to the right
4y=128
y=128/4
y=32
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