y+3(4y+2)=6(y+1)+5y

Solution for y+3(4y+2)=6(y+1)+5y equation:

Simplifying
y + 3(4y + 2) = 6(y + 1) + 5y

Reorder the terms:
y + 3(2 + 4y) = 6(y + 1) + 5y
y + (2 * 3 + 4y * 3) = 6(y + 1) + 5y
y + (6 + 12y) = 6(y + 1) + 5y

Reorder the terms:
6 + y + 12y = 6(y + 1) + 5y

Combine like terms: y + 12y = 13y
6 + 13y = 6(y + 1) + 5y

Reorder the terms:
6 + 13y = 6(1 + y) + 5y
6 + 13y = (1 * 6 + y * 6) + 5y
6 + 13y = (6 + 6y) + 5y

Combine like terms: 6y + 5y = 11y
6 + 13y = 6 + 11y

Add '-6' to each side of the equation.
6 + -6 + 13y = 6 + -6 + 11y

Combine like terms: 6 + -6 = 0
0 + 13y = 6 + -6 + 11y
13y = 6 + -6 + 11y

Combine like terms: 6 + -6 = 0
13y = 0 + 11y
13y = 11y

Solving
13y = 11y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-11y' to each side of the equation.
13y + -11y = 11y + -11y

Combine like terms: 13y + -11y = 2y
2y = 11y + -11y

Combine like terms: 11y + -11y = 0
2y = 0

Divide each side by '2'.
y = 0

Simplifying
y = 0