y+3(4y-7)=7y+15

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Solution for y+3(4y-7)=7y+15 equation: 



y+3(4y-7)=7y+15

We move all terms to the left:

y+3(4y-7)-(7y+15)=0

We multiply parentheses

y+12y-(7y+15)-21=0

We get rid of parentheses

y+12y-7y-15-21=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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