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y+3(y-3)-y(y+5)=6
We move all terms to the left:
y+3(y-3)-y(y+5)-(6)=0
We multiply parentheses
-y^2+y+3y-5y-9-6=0
We add all the numbers together, and all the variables
-1y^2-1y-15=0
a = -1; b = -1; c = -15;
Δ = b2-4ac
Δ = -12-4·(-1)·(-15)
Δ = -59
Delta is less than zero, so there is no solution for the equation
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