y+3-(y-1)=y-2-(-2y+y)

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Solution for y+3-(y-1)=y-2-(-2y+y) equation: 



y+3-(y-1)=y-2-(-2y+y)

We move all terms to the left:

y+3-(y-1)-(y-2-(-2y+y))=0

We add all the numbers together, and all the variables

y-(y-1)-(y-2-(-1y))+3=0

We get rid of parentheses

y-y-(y-2-(-1y))+1+3=0



We calculate terms in parentheses: -(y-2-(-1y)), so:

y-2-(-1y)

determiningTheFunctionDomain
y-(-1y)-2

We get rid of parentheses

y+1y-2

We add all the numbers together, and all the variables

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

-(2y-2)+4=0

We get rid of parentheses

-2y+2+4=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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