y+4(2y-2)=3(y+4)+4

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Solution for y+4(2y-2)=3(y+4)+4 equation: 



y+4(2y-2)=3(y+4)+4

We move all terms to the left:

y+4(2y-2)-(3(y+4)+4)=0

We multiply parentheses

y+8y-(3(y+4)+4)-8=0



We calculate terms in parentheses: -(3(y+4)+4), so:

3(y+4)+4

We multiply parentheses

3y+12+4

We add all the numbers together, and all the variables

3y+16

Back to the equation:

-(3y+16)



We add all the numbers together, and all the variables

9y-(3y+16)-8=0

We get rid of parentheses

9y-3y-16-8=0

We add all the numbers together, and all the variables

6y-24=0

We move all terms containing y to the left, all other terms to the right

6y=24

y=24/6

y=4

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