y+4-4(-4y-1)=2(y-1)

Solution for y+4-4(-4y-1)=2(y-1) equation:

y+4-4(-4y-1)=2(y-1)

We move all terms to the left:

y+4-4(-4y-1)-(2(y-1))=0

We multiply parentheses

y+16y-(2(y-1))+4+4=0


We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)


We add all the numbers together, and all the variables

17y-(2y-2)+8=0

We get rid of parentheses

17y-2y+2+8=0

We add all the numbers together, and all the variables

15y+10=0

We move all terms containing y to the left, all other terms to the right

15y=-10

y=-10/15

y=-2/3