y+4/3y=3318

Solution for y+4/3y=3318 equation:

y+4/3y=3318

We move all terms to the left:

y+4/3y-(3318)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We multiply all the terms by the denominator


y*3y-3318*3y+4=0

Wy multiply elements

3y^2-9954y+4=0

a = 3; b = -9954; c = +4;
Δ = b2-4ac
Δ = -99542-4·3·4
Δ = 99082068
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{99082068}=\sqrt{4*24770517}=\sqrt{4}*\sqrt{24770517}=2\sqrt{24770517}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9954)-2\sqrt{24770517}}{2*3}=\frac{9954-2\sqrt{24770517}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9954)+2\sqrt{24770517}}{2*3}=\frac{9954+2\sqrt{24770517}}{6}
$