y+4/y-3+y-1/y+4

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Solution for y+4/y-3+y-1/y+4 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+y+4/y-(1/y)-3+4 = 0

y+y+4/y-y^-1-3+4 = 0

2*y^1+3*y^-1+1*y^0 = 0

(2*y^2+1*y^1+3*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^2+1*y^1+3*y^0) = 0

y^1

2*y^2+y+3 = 0

2*y^2+y+3 = 0

DELTA = 1^2-(2*3*4)

DELTA = -23

DELTA < 0

y in { } 

y belongs to the empty set

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