y+4/y-3+y-1/y=4

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Solution for y+4/y-3+y-1/y=4 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+y+4/y-(1/y)-3 = 4 // - 4

y+y+4/y-(1/y)-4-3 = 0

y+y+4/y-y^-1-4-3 = 0

2*y^1+3*y^-1-7*y^0 = 0

(2*y^2-7*y^1+3*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^2-7*y^1+3*y^0) = 0

y^1

2*y^2-7*y+3 = 0

2*y^2-7*y+3 = 0

DELTA = (-7)^2-(2*3*4)

DELTA = 25

DELTA > 0

y = (25^(1/2)+7)/(2*2) or y = (7-25^(1/2))/(2*2)

y = 3 or y = 1/2

y in { 1/2, 3} 

y in { 1/2, 3 }

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