y+4X2=11

Solution for y+4X2=11 equation:

y+4y^2=11

We move all terms to the left:

y+4y^2-(11)=0

a = 4; b = 1; c = -11;
Δ = b2-4ac
Δ = 12-4·4·(-11)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{177}}{2*4}=\frac{-1-\sqrt{177}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{177}}{2*4}=\frac{-1+\sqrt{177}}{8}
$