y-(10/y)=3

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Solution for y-(10/y)=3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y-(10/y) = 3 // - 3

y-(10/y)-3 = 0

y-10*y^-1-3 = 0

1*y^1-10*y^-1-3*y^0 = 0

(1*y^2-3*y^1-10*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2-3*y^1-10*y^0) = 0

y^1

y^2-3*y-10 = 0

y^2-3*y-10 = 0

DELTA = (-3)^2-(-10*1*4)

DELTA = 49

DELTA > 0

y = (49^(1/2)+3)/(1*2) or y = (3-49^(1/2))/(1*2)

y = 5 or y = -2

y in { -2, 5} 

y in { -2, 5 }

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