y-(2y+1)=8-3(y+1)

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Solution for y-(2y+1)=8-3(y+1) equation: 



y-(2y+1)=8-3(y+1)

We move all terms to the left:

y-(2y+1)-(8-3(y+1))=0

We get rid of parentheses

y-2y-(8-3(y+1))-1=0



We calculate terms in parentheses: -(8-3(y+1)), so:

8-3(y+1)

determiningTheFunctionDomain
-3(y+1)+8

We multiply parentheses

-3y-3+8

We add all the numbers together, and all the variables

-3y+5

Back to the equation:

-(-3y+5)



We add all the numbers together, and all the variables

-1y-(-3y+5)-1=0

We get rid of parentheses

-1y+3y-5-1=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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