y-(3/4y)=15

Solution for y-(3/4y)=15 equation:

y-(3/4y)=15

We move all terms to the left:

y-(3/4y)-(15)=0


Domain of the equation: 4y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

y-(+3/4y)-15=0

We get rid of parentheses

y-3/4y-15=0

We multiply all the terms by the denominator


y*4y-15*4y-3=0

Wy multiply elements

4y^2-60y-3=0

a = 4; b = -60; c = -3;
Δ = b2-4ac
Δ = -602-4·4·(-3)
Δ = 3648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3648}=\sqrt{64*57}=\sqrt{64}*\sqrt{57}=8\sqrt{57}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-8\sqrt{57}}{2*4}=\frac{60-8\sqrt{57}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+8\sqrt{57}}{2*4}=\frac{60+8\sqrt{57}}{8}
$