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y-(4-3y)/2y-(3+4y)=1/2
We move all terms to the left:
y-(4-3y)/2y-(3+4y)-(1/2)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
y-(-3y+4)/2y-(4y+3)-(+1/2)=0
We get rid of parentheses
y-(-3y+4)/2y-4y-3-1/2=0
We calculate fractions
y-4y-3=0
We add all the numbers together, and all the variables
-3y-3=0
We move all terms containing y to the left, all other terms to the right
-3y=3
y=3/-3
y=-1
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