y-(4-y)=5(y+1)+y

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Solution for y-(4-y)=5(y+1)+y equation: 



y-(4-y)=5(y+1)+y

We move all terms to the left:

y-(4-y)-(5(y+1)+y)=0

We add all the numbers together, and all the variables

y-(-1y+4)-(5(y+1)+y)=0

We get rid of parentheses

y+1y-(5(y+1)+y)-4=0



We calculate terms in parentheses: -(5(y+1)+y), so:

5(y+1)+y

We add all the numbers together, and all the variables

y+5(y+1)

We multiply parentheses

y+5y+5

We add all the numbers together, and all the variables

6y+5

Back to the equation:

-(6y+5)



We add all the numbers together, and all the variables

2y-(6y+5)-4=0

We get rid of parentheses

2y-6y-5-4=0

We add all the numbers together, and all the variables

-4y-9=0

We move all terms containing y to the left, all other terms to the right

-4y=9

y=9/-4

y=-2+1/4

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