y-(5+2y)-5(-2y+1)=2(2y+3)-3(y-4)

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Solution for y-(5+2y)-5(-2y+1)=2(2y+3)-3(y-4) equation:



y-(5+2y)-5(-2y+1)=2(2y+3)-3(y-4)
We move all terms to the left:
y-(5+2y)-5(-2y+1)-(2(2y+3)-3(y-4))=0
We add all the numbers together, and all the variables
y-(2y+5)-5(-2y+1)-(2(2y+3)-3(y-4))=0
We multiply parentheses
y-(2y+5)+10y-(2(2y+3)-3(y-4))-5=0
We get rid of parentheses
y-2y+10y-(2(2y+3)-3(y-4))-5-5=0
We calculate terms in parentheses: -(2(2y+3)-3(y-4)), so:
2(2y+3)-3(y-4)
We multiply parentheses
4y-3y+6+12
We add all the numbers together, and all the variables
y+18
Back to the equation:
-(y+18)
We add all the numbers together, and all the variables
9y-(y+18)-10=0
We get rid of parentheses
9y-y-18-10=0
We add all the numbers together, and all the variables
8y-28=0
We move all terms containing y to the left, all other terms to the right
8y=28
y=28/8
y=3+1/2

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