y-0=(2b/2a-c)(x-c)

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Solution for y-0=(2b/2a-c)(x-c) equation: 


x in (-oo:+oo)

y+0 = (a*((2*b)/2)-c)*(x-c) // - (a*((2*b)/2)-c)*(x-c)

y-((a*((2*b)/2)-c)*(x-c))+0 = 0

y-((a*((2*b)/2)-c)*(x-c)) = 0

y-1*(a*b-c)*(x-c) = 0

y-1*(a*b-c)*(x-c) = 0

a*b*c-(a*b*x)-c^2+c*x+y = 0

a*b*c-(a*b*x)-c^2+c*x+y = 0

a*b*c+c*x-c^2+y = 0 // - a*b*c-c^2+y

c*x = -(a*b*c-c^2+y) // : c

x = (-(a*b*c-c^2+y))/c

x = -(c^-1*(a*b*c-c^2+y))

x = -(c^-1*(a*b*c-c^2+y))

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