y-1/y+2

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Solution for y-1/y+2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y-(1/y)+2 = 0

y-y^-1+2 = 0

1*y^1-1*y^-1+2*y^0 = 0

(1*y^2+2*y^1-1*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2+2*y^1-1*y^0) = 0

y^1

y^2+2*y-1 = 0

y^2+2*y-1 = 0

DELTA = 2^2-(-1*1*4)

DELTA = 8

DELTA > 0

y = (8^(1/2)-2)/(1*2) or y = (-8^(1/2)-2)/(1*2)

y = (2*2^(1/2)-2)/2 or y = (-2*2^(1/2)-2)/2

y in { (-2*2^(1/2)-2)/2, (2*2^(1/2)-2)/2} 

y in { (-2*2^(1/2)-2)/2, (2*2^(1/2)-2)/2 }

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