y-1/y-3=(y-1/y+5)+1

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Solution for y-1/y-3=(y-1/y+5)+1 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y-(1/y)-3 = y-(1/y)+1+5 // - y-(1/y)+1+5

y-y-(1/y)+1/y-5-3-1 = 0

y-y-y^-1+1/y-5-3-1 = 0

-9 = 0

y belongs to the empty set

y belongs to the empty set

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