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y-18/y=12
We move all terms to the left:
y-18/y-(12)=0
Domain of the equation: y!=0We multiply all the terms by the denominator
y∈R
y*y-12*y-18=0
We add all the numbers together, and all the variables
-12y+y*y-18=0
Wy multiply elements
y^2-12y-18=0
a = 1; b = -12; c = -18;
Δ = b2-4ac
Δ = -122-4·1·(-18)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{6}}{2*1}=\frac{12-6\sqrt{6}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{6}}{2*1}=\frac{12+6\sqrt{6}}{2} $
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