y-1=4y-2(y+8)

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Solution for y-1=4y-2(y+8) equation: 



y-1=4y-2(y+8)

We move all terms to the left:

y-1-(4y-2(y+8))=0



We calculate terms in parentheses: -(4y-2(y+8)), so:

4y-2(y+8)

We multiply parentheses

4y-2y-16

We add all the numbers together, and all the variables

2y-16

Back to the equation:

-(2y-16)



We get rid of parentheses

y-2y+16-1=0

We add all the numbers together, and all the variables

-1y+15=0

We move all terms containing y to the left, all other terms to the right

-y=-15

y=-15/-1

y=+15

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